Benda Setinggi 10 cm berdiri tegak di depan cermin cembung berjari-jari 80 cm. Bila jarak benda 60 cm, maka tentukan a. letak bayangan b. perbesaran bayangan c. tinggi bayangan
Ufam
H = 10 cm R = 80 cm h = 60 cm 2/R = 1/f 2/80 = 1/f f = 80 / 2 = ( -40 ) cm a) s' ? s' = f . s / s - f = (-40) . 60 / 60 - (-40) = -2400 / 100 = ( -24 ) cm b) M? M = s' / s = 24 / 60 = 0,4 kali c) h' ? M = h' / h h' = h . M = 10 . 0,4 = 4 cm
R = 80 cm
h = 60 cm
2/R = 1/f
2/80 = 1/f
f = 80 / 2
= ( -40 ) cm
a) s' ?
s' = f . s / s - f
= (-40) . 60 / 60 - (-40)
= -2400 / 100
= ( -24 ) cm
b) M?
M = s' / s
= 24 / 60
= 0,4 kali
c) h' ?
M = h' / h
h' = h . M
= 10 . 0,4
= 4 cm