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b=2,2m
c=50m
d=15m
najpierw obliczmy pole boczne (pole trapezu):
Pt = [(a+b) ÷ 2] × c
Pt = [(0,8m + 2,2m) ÷ 2] × 50m
Pt = (3 ÷ 2) × 50m
Pt = 1,5m × 50m
Pt = 75m²
teraz objętość:
O = Pt × d
O = 75m² × 15m
O = 1125m³
teraz zamieńmy to ma litry
1m³ = 1000dm³
1dm³ = 1l
1125m³ × 1000 = 1 125 000dm³
odp.:
do napełnienia tego basenu potrzeba 1 125 000 litrów wody
pozdrawiam :)