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p = 1050 hPa = 1050 × 100 Pa = 105 000 Pa = 105 000 N/m²
a = 21 cm = 0,21 m
b = 29,7 cm = 0,297 m
szukane:
F = ?
S = a × b = 0,21m × 0,297m = 0,06237 m²
p = F/S |*S
F = p × S = 105000N/m² × 0,06237m²
F = 6 548,85 N
ciśnienie atmosferyczne p = 1050hPa = 105 000Pa
powierzchnia zeszytu S = 21cm · 29,7cm = 623,7cm² = 0,06237m²
siła nacisku F - ?
p = F/S ⇒ F = p ·S
F = 105 000Pa · 0,06237m² = 105 000N/m² · 0,06237m² = 6548,85N
p ≈ 6549N