Question

bardzo prosze o rozwiazanie pilne ;-))))))

Answer 1

1. 

 

2. sin(90°-α) = cosα = ¼

 

3. tgβ = 1½

β ∈ (45°, 60°)

 

4. sinγ = 0,9

γ ∈ (60°, 90°)

 

5. α = 45°

bo cos45° = sin45° = √2/2

 

6. tgβ = 3

ctgβ = ⅓

(3 + ⅓)² = (3⅓)² = 11¹/₉

 

7. cos²40° + cos²50° + cos²60° = sin²50° + cos²50° + (½)² = 1 + ¼ = 1¼

 

cos40° = sin50°