Question

Bardzo prosze o pomoc !

Oblicz wart. wyrażenia stosujac prawa działań na potegach.

Answer 1

a)...=(7^(3-4)):7^-2=7^-1:7^-2=7^(-1-(-2))=

=7^(-1+2)=7^1=7

b)...=(3^-4 : 3^-2)*3^1=3^(-4-(-2)+1)=3^(-4+2+1)=

=3^-1=1/3^1=1/3

c)...=(3/5)^-14 *(5/3)^-16=(3/5)^-14 * (3/5)^16=

=(3/5)^(-14+16)=(3/5)^2=9/25

d)...=((5^3)^3 *5^-4):((5^2)^2*(1/5)^-3)=

=(5^9*5^-4):(5^4*5^3)=5^(9-4):5^(4+3)=

=5^5:5^7=5^(5-7)=5^-2=1/5^2=1/25

e)...=[1,42:(-0,71]^3*0,5^3=(-2)^3*0,5^3=

=((-2)*0,5)^3=(-1)^3=-1

 

a^m * a^n =a^(m*n)

a^m:a^n=a^(m-n)

a^-m =,1/a^m

a^m*b^m=(a*b)^m

 

pozdrawiam;)