bardzo prosze o obliczenie pola podstawy stożka w załączniku
P = Pi*r^2
L = 2*Pi*r
a) r = 12
La = 2*Pi*12*1/4
La = 6Pi
6Pi = 2Pi*r
r = 3
P = Pi*3^2
Pa = 9Pi
b) r = 20
Lb = 2*Pi*20*3/4
Lb = 30Pi
30Pi = 2Pi*r
r = 15
P = Pi*15^2
Pb = 225Pi
c) r = 36
Lc = 2*Pi*36*7/12
Lc = 42Pi
42Pi = 2Pi*r
r = 21
P = Pi*21^2
Pb = 441Pi
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P = Pi*r^2
L = 2*Pi*r
a) r = 12
La = 2*Pi*12*1/4
La = 6Pi
6Pi = 2Pi*r
r = 3
P = Pi*3^2
Pa = 9Pi
b) r = 20
Lb = 2*Pi*20*3/4
Lb = 30Pi
30Pi = 2Pi*r
r = 15
P = Pi*15^2
Pb = 225Pi
c) r = 36
Lc = 2*Pi*36*7/12
Lc = 42Pi
42Pi = 2Pi*r
r = 21
P = Pi*21^2
Pb = 441Pi