Question

Bardzo proszę o pomoc.Wynagrodzę za pomoc :) 2 zadanka z geometrii w załącznikach.

Answer 1

zał. 1

a) sin alfa = 2/3

beta =( 180 - 45 - 90 ) st = 45 st

cos 45 st = p(2)/2

-------------------------------

b)

 cos beta = 3/4

 sin alfa = 3/4

c)

a^2 = 2^2 +1^2 = 4 + 1 = 5

a = p(5)

sin alfa = 1 /p(5) = p(5) / 5

cos beta = 1 / p(5) = p95)/5

d)

h^2 = 4^2 - 1^2 = 16 -1 = 15

h = p(15)

sin alfa = h/4 = p(15) /4

x^2 + h^2 = 5^2

x^2 = 5^2 - h^2

x^2 = 25 - 15 = 10

x = p(10)

cos beta = x/5 = p(10)/5

-----------------------------------------

zał. 2

tg alfa = 1/ 3

a/5 = tg alfa

a/5 = 1/3

3a = 5*1 = 5

a = 5/3

=======

ctg beta = 1/4

 b/10 = ctg beta

b/10 = 1/4

4b = 1*10 = 10

b = 10/4 = 2,5

================

sin gamma = 2/3

3/c = sin gamma

3/c = 2/3

2c = 3*3 = 9

c = 9/2 = 4,5

==============

cos delta = 4/5

d/ 7 = cos delta

d/ 7 = 4/5

5 d = 4*7 = 28

d = 28/5 = 5,6

===============