5dregensleyern III f III f.x III fk 1 ||| 0 ||| 0||| 0 2 ||| 5 III 10 III 5 3 ||| 3 III 9 III 8 4 ||| 8 III 32 III 16 5 ||| 9 III 35 III 25 6 ||| 8 III 48 III 33 Mean = ( 10+9+32+35+48)/33 = 134/33 = 4 me = 1/2.n = 1/2 x 33 = 16,5 data ke = 5 modus = 5
median = 5
modus = 5
maaf kalo salah
1 ||| 0 ||| 0 ||| 0
2 ||| 5 III 10 III 5
3 ||| 3 III 9 III 8
4 ||| 8 III 32 III 16
5 ||| 9 III 35 III 25
6 ||| 8 III 48 III 33
Mean = ( 10+9+32+35+48)/33
= 134/33
= 4
me = 1/2.n
= 1/2 x 33
= 16,5 data ke
= 5
modus = 5