Question

Bantuuu Bg Cara kerja​

Answer 1

Materi Campuran

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Nomor 8

[tex]\begin{aligned} S_{(2≤x≤40)} &= \frac{20}{2} × (2 + 40) \\&= 10 × 42 \\&= \boxed{\bold{\underline{420}}} \end{aligned}[/tex]

Opsi Jawaban : B

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Nomor 9

[tex]\begin{aligned} h(x) &= 3x - 4 \\ h(a) &= 2 \\ 3a - 4 &= 2 \\ 3a &= 2 + 4 \\ 3a &= 6 \\ a &= 2 \end{aligned}[/tex]

Opsi Jawaban : C

[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 12 - 04 - 2023}}[/tex]

Answer 2

Verified answer

Jawaban:

Nomor 8.

Jumlah bilangan genap antara 0 sampai 42 yaitu

• 0 + 2 + 4 + 6 + ... + 42 = ...,
• a = 0
• b = 2
• Un = 42

→ Mencari nilai n

Un = a + (n - 1)b

U42 = 0 + (n - 1)2

U42 = 0 + 2n - 2

2n = 42 + 2

2n = 44

n = 44/2

n = 22

→ Jumlah bilangan genap

Sn = n/2(a + Un)

S22 = 22/2(0 + 42)

S22 = 22/2 × 42

S22 = 22 × 21

S22 = 462

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Nomor 9.

• h(x) = 3x - 4
• h(a) = 2

Mencari nilai a

h(x) = 3x - 4

h(a) = 2

h(a) = 3a - 4 = 2

3a = 2 + 4

3a = 6

a = 6/3

a = 2

'비상'