BArisan dan DEretAritmatika
Penjelasan dengan langkah-langkah:
U8 = 23u30 = 89tentukan S50
u30 - u8 = 89-2322b = 66b = 3
u8 = 23a + 7b = 23a+ 7(3) = 23a+ 21= 23a= 2
jumlah 50 suku = S50Sn = n/2 { 2a + (n-1) b}s50= 50/2 { 2 (2) + 49(3)}s50 = 25 (4 + 147)s50 = 3.775
U8 = a + 7b = 23
U30 = a + 29b = 89
a + 29b = 89
a + 7b = 23
--------------------
29b - 7b = 89 - 23
22b = 66
b = 66/22
b = 3
a + 7 × 3 = 23
a + 21 = 23
a = 23 - 21
a = 2
Sn = n/2 (2a + (n - 1) b)
S50 = 50/2 (2 × 2 + (50 - 1) 3)
S50 = 25 (4 + 49 × 3)
S50 = 25 (4 + 147)
S50 = 25 × 151
S50 = 3.775
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BArisan dan DEret
Aritmatika
Penjelasan dengan langkah-langkah:
U8 = 23
u30 = 89
tentukan S50
u30 - u8 = 89-23
22b = 66
b = 3
u8 = 23
a + 7b = 23
a+ 7(3) = 23
a+ 21= 23
a= 2
jumlah 50 suku = S50
Sn = n/2 { 2a + (n-1) b}
s50= 50/2 { 2 (2) + 49(3)}
s50 = 25 (4 + 147)
s50 = 3.775
S50 = 3.775
Penjelasan dengan langkah-langkah:
U8 = a + 7b = 23
U30 = a + 29b = 89
Eliminasi a
a + 29b = 89
a + 7b = 23
--------------------
29b - 7b = 89 - 23
22b = 66
b = 66/22
b = 3
Substitusi b
a + 7b = 23
a + 7 × 3 = 23
a + 21 = 23
a = 23 - 21
a = 2
50 suku pertama
Sn = n/2 (2a + (n - 1) b)
S50 = 50/2 (2 × 2 + (50 - 1) 3)
S50 = 25 (4 + 49 × 3)
S50 = 25 (4 + 147)
S50 = 25 × 151
S50 = 3.775