Question

bantuu kak
jan ngasal
makasii​

Answer 1

Jawaban:

A. {1/12π, ⅓π, 7/12π, 5/6π, 13/12π, 4/3π, 19/12π, 11/6π }

Penjelasan dengan langkah-langkah:

tan 4x = tan ⅓ π untuk 0 ≤ x ≤ 2π

jawab :

tan 4x = tan ⅓π, maka

4x = ⅓π + k . π

x = 1/12 π + k . ¼π

k = 0 → x = 1/12 π + 0 . ¼π = 1/12π

k = 1 → x = 1/12 π + 1 . ¼π = ⅓π

k = 2 → x = 1/12 π + 2 . ¼π = 7/12π

k = 3 → x = 1/12 π + 3 . ¼π = 5/6π

k = 4 → x = 1/12 π + 4 . ¼π = 13/12π

k = 5 → x = 1/12 π + 5 . ¼π = 4/3π

k = 6 → x = 1/12 π + 6 . ¼π = 19/12π

k = 7 → x = 1/12 π + 7 . ¼π = 11/6π