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dik;
a = 5 dan b = 9
Un = a + (n-1) b
239 = 5 + (n-1)9
239 = 5 + 9n - 9
239 = 9n-4
243 = 9n
n = 27
b. dik : U3 = 9 dan U7 = 49
U3 --> a+(3-1)b = 9 => a + 2b = 9
U7 --> a+(7-1)b = 49 => a + 6b = 49
coret yang sama, jadi :
-4b = -40
b = 10
substitusi ke salah satu soal (saya ambil yg U3)
a+2b = 9
a+2(10) = 9
a+20 = 9
a = -11
U13 = a+(n-1)b
U13 = -11+(13-1)10
U13 = 109
Un = a+(n-1)b
179 = -11+(n-1)10
179 = -11+10n-10
179 = 10n-21
200 = 10n
n = 20