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Verified answer
Hambatan total
1/R = 1/(4+4) + 1/(2+2+2)
1/R = 1/8 + 1/6 = 7/24
R = 24/7 Ω
Kuat arus induk
V = i R
i = V / R
i = 24 / (24/7)
i = 7 A
kuat arus ini terpecah dua menjadi i₁ dan i₂ dengan perbandingan
i₁ : i₂ = 1/8 : 1/6 = 3 : 4
jadi
i₁ = 3/(3+4) × {7 A) = 3 A
melewati R₁ dan R₂
dan
i₂ = 4/(3+4) × (7 A) = 4 A
melewati R₃, R₄ dan R₅
jawaban [b] ✓