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Jari-hari alas kerucut = 5 cm.
Luas selimut kerucut = 65π cm².
Dit : Volume kerucut.
Jawab:
Luas selimut kerucut = πrs
65π = 5 × s
65 ÷ 5 = s (π dieliminasi dulu)
13 = s.
Tinggi kerucut² = s² - r²
t² = 13² - 5²
t² = 169 - 25
t = √144
t = 12.
Volume kerucut = ⅓πr²t
V = ⅓ × π × 5² × 12
V = 4 × π × 25
V = 100 π cm³
D. 100 π cm³