Question

Bantuin dong yg tau hehe

Answer 1

Luas = D√D / 6a^2 dg D = b^2 - 4ac karena hanya dibatasi 2 kurva
1. y1 - y2 = (x^2 - 2x) - 4x = x^2 - 6x => D = (-6)^2 - 4(1)(0) = 36 maka
luasnya = 36√36 / 6(1)^2 = 36

2. y1 - y2 = x^2 - (2 - x^2) = 2x^2 - 2 => D = 0^2 - 4(2)(-2) = 16 maka
luasnya = 16√16 / 6(2)^2 = 16.4 / 6.4 = 8/3

no 3 dan 4 ga dapat

4. y1 - y2 = (4 - x^2) - (x + 3) = -x^2 - x + 1 => D = (-1)^2 - 4(-1)(1)