Noven99
Diket : r = 28 cm π = 22/7 Luas seluruh / luas permukaan kerucut = 5.544 cm² Ditanya : a. panjang garis pelukis b. tinggi kerucut c. volume kerucut Jawab: a. Lp = Ls + L lingkaran 5.544 = πrs + πr² 5.544 = πr (s + r) 5.544 = 22/7 x 28 (s + 28) 5.544 = 88 ( s + 28) 5.544 / 88 = s + 28 63 = s + 28 → s = 63 - 28 → s = 35 cm
b. Tinggi kerucut = = = = Tinggi kerucut = 21 cm
c. Volume kerucut = 1/3 x La x t = 1/3 x πr² x t = 1/3 x 22/7 x 28 x 28 x 21 = 2464 x 7 = 17.248 cm³
r = 28 cm
π = 22/7
Luas seluruh / luas permukaan kerucut = 5.544 cm²
Ditanya : a. panjang garis pelukis
b. tinggi kerucut
c. volume kerucut
Jawab:
a. Lp = Ls + L lingkaran
5.544 = πrs + πr²
5.544 = πr (s + r)
5.544 = 22/7 x 28 (s + 28)
5.544 = 88 ( s + 28)
5.544 / 88 = s + 28
63 = s + 28 → s = 63 - 28 → s = 35 cm
b. Tinggi kerucut =
=
=
=
Tinggi kerucut = 21 cm
c. Volume kerucut = 1/3 x La x t
= 1/3 x πr² x t
= 1/3 x 22/7 x 28 x 28 x 21
= 2464 x 7
= 17.248 cm³
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