Question

Bantuin 3 nomer itu dong makasihhhh yaaa pointnya banyai nih bantuin dgn benar ya

Answer 1

Verified answer

55][ Gaya Listrik
Qa = 10 μC = 10×10⁻⁶ C
Qb = - 10 μC = -10×10⁻⁶ C
Qc = 2 μC = 2×10⁻⁶ C
r = 20 cm = 0,2 m
cos α = 5/20 = ¼

Gaya pada C oleh A
Fca = k Qc Qa / r²
Fca = 9×10⁹ • 2×10⁻⁶ • 10×10⁻⁶ / 0,2²
Fca = 4,5 N menjauhi A

Gaya pada C oleh B
Fcb = k Qc Qb / r²
Fcb = 4,5 N menuju B

Resultan gaya pada C
Fc = Fca cos α + Fcb cos α
Fc = 2 • 4,5 • ¼
Fc = 9/4 = 2,25 N ← jwb



56][ Energi potensial ??
solenoida
N = 10³
L = 1 m
r = 0,1 m
i = 10 m

induktansi solenoida
L = μ₀ N²/L A
L = μ₀ N²/L • π r²

energi potensial
Ep = ½ L i²
Ep = ½ • μ₀ N²/L • π r² • i²
Ep = ½ • 4π×10⁻⁷ • (10³)²/1 • π•0,1² • 10²
Ep = π²/5 ≈ 2 J ← jwb



57][ Gaya magnet
q = 1,6×10⁻¹⁹ C
B = (0,1 j) T
v = (100 i) m/s
F = __?

F = q • v × B
F = 1,6×10⁻¹⁹ • ( 100 i × 0,1 j )
F = 1,6×10⁻¹⁹ • 10 k
F = (1,6×10⁻¹⁸ k) N ← jwb