1. Diberikan segitiga ABC siku-siku di A. AB = 21 cm, BC = 35 cm, maka AC = √(35² – 21²) = √(1.225 – 441) = √784 = 28 s = 1/2 (21 + 35 + 28) = 1/2 (84) = 42 L = √{s(s – AB)(s – BC)(s – AC)} = √{42(42 – 21)(42 – 35)(42 – 28)} = √{42(21)(7)(14)} = √86.436 = 294 Jari-jari lingkaran luar: R = (AB × BC × AC)/4L = (21 × 35 × 28)/4(294) = 5.880/1.176 = 5 cm
2. L alas kubus = 25 cm², maka panjang rusuk kubus = r = √25 = 5 cm Volume kubus = r³ = 5³ = 125 cm³
3.Roda berdiameter 49 cm memiliki keliling K = π d = 22/7 (49) = 154 cm Roda berputar 2000 kali, maka jarak tempuh = 2000 × 154 = 308.000 cm = 3,08 km
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1. Diberikan segitiga ABC siku-siku di A.
AB = 21 cm, BC = 35 cm, maka
AC = √(35² – 21²) = √(1.225 – 441) = √784 = 28
s = 1/2 (21 + 35 + 28) = 1/2 (84) = 42
L = √{s(s – AB)(s – BC)(s – AC)}
= √{42(42 – 21)(42 – 35)(42 – 28)}
= √{42(21)(7)(14)}
= √86.436 = 294
Jari-jari lingkaran luar:
R = (AB × BC × AC)/4L
= (21 × 35 × 28)/4(294)
= 5.880/1.176
= 5 cm
2. L alas kubus = 25 cm², maka
panjang rusuk kubus = r = √25 = 5 cm
Volume kubus = r³ = 5³ = 125 cm³
3.Roda berdiameter 49 cm memiliki keliling
K = π d = 22/7 (49) = 154 cm
Roda berputar 2000 kali, maka
jarak tempuh = 2000 × 154 = 308.000 cm = 3,08 km