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mA = 0.2 kg
mB = 0.4 kg
ωA = 2ω
ωB = ω
ω AB = . . . . . . ?
Penyelesaian
–Hukum Kekekalan Momentum Sudut–
L sebelum = L sesudah
I A . ωA + I B . ωB = (I A + I B) . ωAB
mA . RA². ωA + mB . RB² . ωB = (mA . RA² + mB . RB²) . ωAB
0.2 . R² . 2ω + 0.4. R² . ω = (0.2 . R² + 0.4 . R²) . ωAB
0.4ωR² + 0.4ωR² = 0.6R² . ω AB
0.8ωR² = 0.6R². ω AB
0.8ω = 0.6 . ω AB
ω AB = 0.8ω/0.6
ω AB = 8ω/6
ω AB = 4ω/3
ω AB = ⁴/₃ω
Jadi, kecepatan sudutnya akan menjadi ⁴/₃ω (Jawaban D)