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ω=2t+6t² rad/s
θo=0
Ditanyakan: θ sebagai fungsi waktu ?
Dijawab:
Gunakan konsep integral:
Ingat!
∫axⁿ = 1 aⁿ⁺¹ +C
n+1
θ=θo+∫ω dt
=0+∫(2t+6t²) dt
= 2 t¹⁺¹ + 6t²⁺¹ +C
1+1 2+1
=t²+2t³ +C
Cheers :D