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diketahui :
R = 4Ω
R2 = 3Ω
R3 = 6Ω
V = 6 V
ditanyakan :
I = ?
jawab :
menghitung R2 dan R3
1/R = 1/R2 + 1/R3
1/R = 1/3 + 1/6
1/R = 2/6 + 1/6 = 3/6
R = 6/3 = 2Ω
menghitung R total ( R1 dg R2,3)
R tot = R1 + R
R tot = 4 + 2 = 6Ω
menghitung I
I = V/R tot
I = 6/6 = 1 A
jadi besar arus listriknya dalah 1 A
13)
diketahui :
I = 7,5 A
I1 = 0,5 A
I5 = 2,5 A
I3 = 1 A
ditanyakan:
I4 = ?
jawab :
I masuk = I keluar
I = I1 +I2 + I3
7,5 = 0,5 + I2 + 1
7,5 = 1,5 + I2
I2 = 6 A
I2 = I4 + I5
6 = I4 + 2,5
I4 = 6 - 2,5
I4 = 3,5 A