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F₁ = 30 N
F₃ = 25 N
a = 3 m/s²
m = 5 kg
F₂ = ....?
benda bergerak ke kanan :
∑F = m . a
F₂ + F₁ - F₃ = 5 . 3
F₂ + 30 - 25 = 15
F₂ = 15 - 30 + 25
F₂ = 10 N
jadi besar F₂ nya adalah 10 Newton
diketahui:
m = 5 kg
F1 = 30 N
F3 = 25 N
a = 3 m/s²
ditanya:
F2?
jawab:
Resultan gaya
ΣF = m a
ΣF = 5 . 3
ΣF = 15 N
maka nilai F2
F2 = ΣF + F3 - F1
F2 = 15 + 25 - 30
F2 = 40 - 30
F2 = 10 N ke kanan