Jawaban:
17. e. (15, -18)
18. a. (10, -12)
Penjelasan dengan langkah-langkah:
Transformasi geometri
Refleksi (pencerminan)
[tex] \small \boxed{\begin{array}{l | l} rumus & matriks \\ A(x,y) \xrightarrow{\: \:M_{x}\: \:}A'(x,-y)& \begin{pmatrix}1&0\\0&-1\end{pmatrix} \\A(x,y) \xrightarrow{ \: \: M_{y} \: \: }A'(-x,y)& \begin{pmatrix}-1&0\\0&-1\end{pmatrix}\\A(x,y) \xrightarrow{\: \:M_{y=x}\: \:}A'(y,x)& \begin{pmatrix}0&1\\1&0\end{pmatrix}\\A(x,y) \xrightarrow{\: \:M_{y=-x}\: \:}A'(-y,-x)& \begin{pmatrix}0&-1\\-1&0\end{pmatrix}\\A(x,y) \xrightarrow{\: \:M_{O}\: \:}A'( - x, - y)& \begin{pmatrix}-1&0 \\ 0&-1\end{pmatrix}\\A(-x,-y) \xrightarrow{\: \:M_{x=h}\: \:}A'(2h-x,y)& \begin{pmatrix}-1&0\\0&1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}+ \begin{pmatrix}2h\\0\end{pmatrix}\\A(x,y) \xrightarrow{\: \:M_{y=h}\: \:}A'(x,2h-y) &\begin{pmatrix}1&0\\0&-1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}+ \begin{pmatrix}0\\2h\end{pmatrix}\end{array}}[/tex]
[tex]_____________________[/tex]
penyelesaian
17. Q(15, 18) dicerminkan terhadap sumbu x maka Q'
rumus pencerminan terhadap sumbu x:
[tex] \boxed{A(x,y) \xrightarrow{\: \:M_{x}\: \:}A'(x,-y)}[/tex]
maka
[tex]Q(15,18) \xrightarrow{\: \:M_{x}\: \:}Q'(15,-18)[/tex]
opsi (e)
[tex]__________[/tex]
titik (12, -10) dicerminkan terhadap x =-y, maka koordinat bayangannya adalah
rumus pencerminan terhadap sumbu x =-y
[tex] \boxed{A(x,y) \xrightarrow{\: \:M_{y=-x}\: \:}A'(-y,-x)}[/tex]
[tex](12, - 10) \xrightarrow{\: \:M_{y=-x}\: \:}(10, - 12)[/tex]
opsi((a)
jawaban terlampir pada gambar yaa
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawaban:
17. e. (15, -18)
18. a. (10, -12)
Penjelasan dengan langkah-langkah:
Transformasi geometri
Refleksi (pencerminan)
[tex] \small \boxed{\begin{array}{l | l} rumus & matriks \\ A(x,y) \xrightarrow{\: \:M_{x}\: \:}A'(x,-y)& \begin{pmatrix}1&0\\0&-1\end{pmatrix} \\A(x,y) \xrightarrow{ \: \: M_{y} \: \: }A'(-x,y)& \begin{pmatrix}-1&0\\0&-1\end{pmatrix}\\A(x,y) \xrightarrow{\: \:M_{y=x}\: \:}A'(y,x)& \begin{pmatrix}0&1\\1&0\end{pmatrix}\\A(x,y) \xrightarrow{\: \:M_{y=-x}\: \:}A'(-y,-x)& \begin{pmatrix}0&-1\\-1&0\end{pmatrix}\\A(x,y) \xrightarrow{\: \:M_{O}\: \:}A'( - x, - y)& \begin{pmatrix}-1&0 \\ 0&-1\end{pmatrix}\\A(-x,-y) \xrightarrow{\: \:M_{x=h}\: \:}A'(2h-x,y)& \begin{pmatrix}-1&0\\0&1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}+ \begin{pmatrix}2h\\0\end{pmatrix}\\A(x,y) \xrightarrow{\: \:M_{y=h}\: \:}A'(x,2h-y) &\begin{pmatrix}1&0\\0&-1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}+ \begin{pmatrix}0\\2h\end{pmatrix}\end{array}}[/tex]
[tex]_____________________[/tex]
penyelesaian
17. Q(15, 18) dicerminkan terhadap sumbu x maka Q'
rumus pencerminan terhadap sumbu x:
[tex] \boxed{A(x,y) \xrightarrow{\: \:M_{x}\: \:}A'(x,-y)}[/tex]
maka
[tex]Q(15,18) \xrightarrow{\: \:M_{x}\: \:}Q'(15,-18)[/tex]
opsi (e)
[tex]__________[/tex]
titik (12, -10) dicerminkan terhadap x =-y, maka koordinat bayangannya adalah
rumus pencerminan terhadap sumbu x =-y
[tex] \boxed{A(x,y) \xrightarrow{\: \:M_{y=-x}\: \:}A'(-y,-x)}[/tex]
maka
[tex](12, - 10) \xrightarrow{\: \:M_{y=-x}\: \:}(10, - 12)[/tex]
opsi((a)
jawaban terlampir pada gambar yaa