V.BALOK :
= (14(25(10)
= (14(250)
= 3.500 CM³
V.1/2 TABUNG :
R = 14/2 = 7 CM
= 1/2(πR²T)
= 1/2(22/7(7²(25)
= 1/2(22/7(49(25)
= 1/2(22/7(1.225)
= 1/2(22(1.225/7)
= 1/2(22(175)
= 1/2(3.850)
= 3.850/2
= 1.925 CM³
V.GAB :
= 3.500 + 1.925
= 5.425 CM³
[tex]{\color{aqua}{\boxed{\tt{CaptainInnovaGR}}\:}}[/tex]
Jawaban:
Luas permukaan bangun gabungan = 2.184 cm²
Penjelasan dengan langkah-langkah:
rumus mencari luas permukaan balok = 2 × ( pl + pt + It )
= 2 × ( 25 × 14 + 25 × 10 + 14 × 10 )
= 1.480 cm²
rumus mencari luas permukaan tabung = 2 π × r ( r + t )
= 2 × 22/7 × 7 × ( 7 + 25 )
= 1.408 × ½
= 704 cm²
Luas permukaan bangun gabungan = 1.480 + 704 = 2.184 cm²
#Semangat belajar#
Semoga bermanfaat terimakasih
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V.BALOK :
= (14(25(10)
= (14(250)
= 3.500 CM³
V.1/2 TABUNG :
R = 14/2 = 7 CM
= 1/2(πR²T)
= 1/2(22/7(7²(25)
= 1/2(22/7(49(25)
= 1/2(22/7(1.225)
= 1/2(22(1.225/7)
= 1/2(22(175)
= 1/2(3.850)
= 3.850/2
= 1.925 CM³
V.GAB :
= 3.500 + 1.925
= 5.425 CM³
[tex]{\color{aqua}{\boxed{\tt{CaptainInnovaGR}}\:}}[/tex]
Jawaban:
Luas permukaan bangun gabungan = 2.184 cm²
Penjelasan dengan langkah-langkah:
rumus mencari luas permukaan balok = 2 × ( pl + pt + It )
= 2 × ( 25 × 14 + 25 × 10 + 14 × 10 )
= 1.480 cm²
rumus mencari luas permukaan tabung = 2 π × r ( r + t )
= 2 × 22/7 × 7 × ( 7 + 25 )
= 1.408 × ½
= 704 cm²
Luas permukaan bangun gabungan = 1.480 + 704 = 2.184 cm²
#Semangat belajar#
Semoga bermanfaat terimakasih