Penjelasan dengan langkah-langkah:
(f-¹ o g)(x) = x + 1
g(x) = 3x – 5
misal g(x) = y
y = 3x – 5
3x = y + 5
x = ⅓(y + 5)
g-¹(x) = ⅓(x + 5)
(f-¹(3x – 5) = x + 1
f-¹(x) = g-¹(x) + 1
f-¹(x) = ⅓(x + 5) + 1
f-¹(x) = ⅓x + 5/3 + 3/3
f-¹(x) = ⅓x + 8/3
f-¹(x) = ⅓(x + 8)
misal f-¹(x) = k
k = ⅓(x + 8)
3k = x + 8
x = 3k – 8
f(x) = 3x – 8
f(1) = 3(1) – 8
Jawab:-5
Penjelasan:Diketahui:(f⁻¹og)(x) = x+1g(x) = 3x - 5
Ditanya nilai f(1)(f⁻¹og)(x) = f⁻¹(g(x))x+1 = f⁻¹(3x - 5)f⁻¹(3x - 5) = x+1
Misal k = g(x)k = 3x-53x = k+5x = (k+5)/3
makaf⁻¹(k) = ((k+5)/3) + 1f⁻¹(k) = ((k+5)/3) + (3/3)f⁻¹(k) = (k+8)/3f⁻¹(x) = (x+8)/3
Cari inversnyay = (x+8)/3Ganti x dengan yx = (y+8)/3y+8 = 3xy = 3x-8f(x) = 3x-8
Maka f(1) = 3(1)-8 =-5
( x c v i )
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Penjelasan dengan langkah-langkah:
(f-¹ o g)(x) = x + 1
g(x) = 3x – 5
misal g(x) = y
y = 3x – 5
3x = y + 5
x = ⅓(y + 5)
g-¹(x) = ⅓(x + 5)
(f-¹(3x – 5) = x + 1
f-¹(x) = g-¹(x) + 1
f-¹(x) = ⅓(x + 5) + 1
f-¹(x) = ⅓x + 5/3 + 3/3
f-¹(x) = ⅓x + 8/3
f-¹(x) = ⅓(x + 8)
misal f-¹(x) = k
k = ⅓(x + 8)
3k = x + 8
x = 3k – 8
f(x) = 3x – 8
f(x) = 3x – 8
f(1) = 3(1) – 8
f(1) = –5
Jawab:
-5
Penjelasan:
Diketahui:
(f⁻¹og)(x) = x+1
g(x) = 3x - 5
Ditanya nilai f(1)
(f⁻¹og)(x) = f⁻¹(g(x))
x+1 = f⁻¹(3x - 5)
f⁻¹(3x - 5) = x+1
Misal k = g(x)
k = 3x-5
3x = k+5
x = (k+5)/3
maka
f⁻¹(k) = ((k+5)/3) + 1
f⁻¹(k) = ((k+5)/3) + (3/3)
f⁻¹(k) = (k+8)/3
f⁻¹(x) = (x+8)/3
Cari inversnya
y = (x+8)/3
Ganti x dengan y
x = (y+8)/3
y+8 = 3x
y = 3x-8
f(x) = 3x-8
Maka f(1) = 3(1)-8 =
-5
( x c v i )