Jawaban:
1. F = 180 N
2. EB = 150 N/C
3. QB = 8.10⁻¹² C
Penjelasan:
1. Gaya Coulomb
F = k.q1.q2/r² = 9.10⁹. 2.10⁻⁶. 4.10⁻⁶/(2.10⁻²)²
F = 180 N
2. Medan listrik EB yang dirasakan muatan A disebabkan oleh muatan B yaitu QB.
EB = k.QB/r² --> kuat medan di A disebabkan B
F = k.QA.QB/r² = QA. EB
EB = F/QA = 3.10⁻⁴ / 2.10⁻⁶
EB = 150 N/C
3. EB = k.QB/r² --> kuat medan di A disebabkan B
QB = EB. r²/k = 80. (3.10⁻²)²/(9.10⁹)
QB = 8.10⁻¹² C
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Jawaban:
1. F = 180 N
2. EB = 150 N/C
3. QB = 8.10⁻¹² C
Penjelasan:
1. Gaya Coulomb
F = k.q1.q2/r² = 9.10⁹. 2.10⁻⁶. 4.10⁻⁶/(2.10⁻²)²
F = 180 N
2. Medan listrik EB yang dirasakan muatan A disebabkan oleh muatan B yaitu QB.
EB = k.QB/r² --> kuat medan di A disebabkan B
F = k.QA.QB/r² = QA. EB
EB = F/QA = 3.10⁻⁴ / 2.10⁻⁶
EB = 150 N/C
3. EB = k.QB/r² --> kuat medan di A disebabkan B
QB = EB. r²/k = 80. (3.10⁻²)²/(9.10⁹)
QB = 8.10⁻¹² C