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%urea = 2,4%
MR Urea = 60
Kb air = 0,52
Ditanya
Tb
Jawab
Misal massa larutan = 100 gram
Massa urea = 2,4% X 100 gram = 2,4 gram
Massa pelarut(air) = 100 gram - 2,4 gram = 97,6 gram
m urea = gram/MR x 1000/massa pelarut
= 2,4/60 x 1000/97,6
= 0,04 x 10,24 = 0,4096
delta Tb = Kb x m = 0,52 x 0,4096= 0,212992 derajat c/m
maka Delta Tb = Tb larutan - Tb pelarut (air)
Tb larutan = delta Tb + Tb pelarut (air)
Tb larutan = 0,212992 + 100 (titikdidih air)
Tb larutan = 100,212992 derajat c
Maaf kalo salah