Question

bantu jawab kak soal terlampir kan​

Answer 1

Penjelasan dengan langkah-langkah:

1. Q'(7-12, 5-12) = (-5, -7)

2. P'(-2+4, 3-2-2) = (2, -1)

3. F' = 3(-1, 2) = (-3, 6)

F" = (1+3, 2-6) = (4, -4)

4. M = (-1-4, 4+3) = (-5, 7)

5. K'(-3-3, -2+4) = (-6, 2) ===> K"(12, -4)

L'(4-3, -2+4) = (1, 2) ===> L"(-2 , -4)

M'(4-3, 2+4) = (1, 6) ===> M"(-2, -12)

N'(-3-3, 2+4) = (-6, 6) ===> N"(12, -12)

Answer 2

Jawab:

1. (-5, -7)
2. (4, 6)
3. (-3, 6)
4. (-5, 7)
5. Transformasi:
K= (12, -4)
L= (-2, -4)
M= (-2, -12)
N= (12, -12)

Penjelasan dengan langkah-langkah:

1.
Rumus refleksi y= -x
(x, y) -> (-y, -x)
(7, 5)-> (-5, -7)
2.
Rumus refleksi y= k
(x, y) -> (x, 2k-y)
y=2, maka:
(4, 2(2)- (-2))
= (4,  4+2)
= (4, 6)
3.
Dilatasi faktor skala k dengan pusat O adalah:
(x, y)-> (kx, ky)
(-1, 2)-> (3(-1), 3(2))
= (-3, 6)
Lalu dirotasi 180 dengan pusat (1, 2)
Translasikan dengan (-1, -2)
= (-3-1, 6-2)
= (-4, 4)

Lalu rotasi 180:
(x, y) -> (-x, -y)
(-4, 4)-> (-(-4), -4)
= (4, -4)
4.
Ingat rumus translasi (x, y) dengan (a, b)
(x+a, y+b)
= (-1, 4)
x+a= -1
x+4= -1
x= -5
y+b= 4
y-3= 4
y= 7
Titik awal= (-5, 7)
5.
K(-3, -2) -> (-3+ -3. -2+4) -> (-6, 2)
Dilatasi lagi faktor skala -2:
(-2(-6), 2(-2))
= (12, -4)
L(4, -2) -> (4+-3, -2+4)-> (1, 2)
-> (-2(1), -2(2))
= (-2, -4)
M(4, 2)-> (4+(-3), 2+4) -> (1, 6)
-> (-2(1), -2(6))
-> (-2, -12)
N(-3, 2)-> (-3+-3, 2+4)-> (-6, 6)
-> (-2(-6), -2(6))
-> (12, -12)