Jawab:
Penjelasan dengan langkah-langkah:
jawab
1 + 3+ 5+...+(2n-1)=n²
n=1 → 1 = 1
n = k → 1+ 3 + 5 +...+(2k -1) =k²
n = k+1 → {1 + 3+ 5 + ..+ (2k-1)} + 2(k+1) -1 = (k+1)²
k² + 2(k+1) - 1 = (k+1)²
k² + 2k + 2 - 1 = (k+1)²
k² + 2k + 1 = (k+1)²
(k+1)² = (k+1)²
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Jawab:
Penjelasan dengan langkah-langkah:
Jawab:
Penjelasan dengan langkah-langkah:
jawab
1 + 3+ 5+...+(2n-1)=n²
n=1 → 1 = 1
n = k → 1+ 3 + 5 +...+(2k -1) =k²
n = k+1 → {1 + 3+ 5 + ..+ (2k-1)} + 2(k+1) -1 = (k+1)²
k² + 2(k+1) - 1 = (k+1)²
k² + 2k + 2 - 1 = (k+1)²
k² + 2k + 1 = (k+1)²
(k+1)² = (k+1)²