Question

Bantu Jawab Guys No.1 dan 2 Pakai Cara ya Guys

Answer 1

1. Diketahui
Massa glukosa = 45 gram
MR glukosa = 180
Gram pelarut = 400 gram
Kf air = 1,86
Ditanya Tf larutan glukosa
Jawab
m glukosa = gram / Mr x 1000/massa pelarut
                 = 45 gram / 180 x 1000/400gram
                 = 0,25 x 2,5 = 0,625 m
delta Tf = kf x m = 1,86 x 0,625 = 1,1625 derajat c/m
delta tf = tf pelarut - tf larutan
- Tf larutan = tf pelarut + delta tf
- tf larutan = 0 + 1,1625 = -1,1625 derajat c.





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