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=( x³y^6/x⁴y^-3) x (xy^-4/x^7y)
=( x⁴y²)/(x¹¹y^-2) = x^-7.y⁴
Jawaban : B.
9. (4/8)^1/2 + (8/27)^1/3 + (16/81)^1/4 = (2²/2³)^1/2 + (2³/3³)^1/3 + (2⁴/3⁴)^1/4 = 2^-1)^1/2 + 2/3 + 2/3 = 2^-1/2 + 4/3 = 1/√2 + 4/3 = (3 + 4√2)/3√2 x √2/√2 = (3√2 + 8)/6