Question

Bantu donk kak bang :')

Answer 1

1)
Luas selimut kerucut = π r s
mencari nilai s
= √(t² + r²)
= √(24² + 7²)
= √625
= 25 cm
Luas selimut kerucut = 22/7 x (7 cm)  x (25 cm)
Luas selimut kerucut = 550 cm²

2)
mencari nilai s
= √(15² + 8²)
= 17 cm
Luas selimut kerucut = 3,14 x (8 cm) x (17 cm)
Luas selimut kerucut = 427,04 cm²

3)
π r s = 7656
22/7 x (42 cm) x s = 7656 cm²
s = 7657 cm² : 132 cm
s = 58 cm
mencari tinggi kerucut
= √(s² - r²)
= √(58² - 42²)
= 40 cm

4)
π r s = 1232 cm²
22/7 x (7 cm) x s = 1232 cm²
s = 1232 cm² : 22 cm
s = 56 cm

5)
2 π r = 88 cm
2 x 22/7 x r = 88 cm
r = 88 cm x 7/44
r = 14 cm
mencari tinggi kerucut
= √(s² - r²)
= √(25² - 14²)
= 20,71
mencari volume kerucut
= {πr²t} : 3
= { 22/7 x (14 cm)² x (20,71) : 3
= 46.777 cm³