Question

BANTU AKU MENGERJAKAN SOAL NOMOR 21 INI... TQ YAA

Answer 1

Cari persamaan yg tegak lurus dulu

x - x1 / x2-x1 = y-y1 / y2 -y1
x + 5 / 10 = y-6 /-10
-10x - 50 = 10y - 60
-x - 5 = y - 6 (dibagi 10 semua, biar lbh sederhana)
y-6 + x + 5 = 0
y + x -1 = 0
M1 = -1

m2 = -1 : m1
m2 = -1: -1
m2 = 1

persamaan yg melewati titik (-1,6)

m (x-x1) = y -y1
1 (x +1) = y - 6
x + 1 = y -6
x + 1 - y + 6
x -y + 7 = 0
y= x + 7 Jawab :  C