Błaham niech ktoś rozwiążę mi to równanie metodą podstawiania !
x+y=3
x-2y=6
Z góry dzięki !
x=3-y
3-y-2y=6
-3y=6-3
-3y=3/:(-3)
y=-1
x=3-(-1)
x=3+1
x=4
x+y =3
x-2y =6
x =3-y
-3y=3 / /-3
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x+y=3
x-2y=6
x=3-y
3-y-2y=6
x=3-y
-3y=6-3
x=3-y
-3y=3/:(-3)
x=3-y
y=-1
x=3-(-1)
y=-1
x=3+1
y=-1
x=4
y=-1
x+y =3
x-2y =6
x =3-y
x-2y =6
3-y-2y=6
x=3-y
-3y=3 / /-3
x=3-y
y=-1
x=3-(-1)
y=-1
x=4
y=-1