Question

Błagam dma naj zad 58,59

Answer 1

58

a) P = d/M * RT / :RT

P/RT = d/M / *d

M = P/RT * d

 

b) f = 9/5c + 32

f - 32 = 9/5 c / : 9/5

(f - 32) * 5/9 = c

c = 5/9f - 160/9

c = 5/9f - 17 i 7/9

 

c) s = vt + at^/2

s - vt = at^/2 / * 2

2(s - vt) = at^ / :t^

a = (2s - 2vt) : t^

 

d) F = GMm/r^ / *r^

Fr^ = GMm / : GM

m = Fr^/GM

 

59

a) t = x/a - 5x

t = x (1/a - 5) / : (1/a - 5)

x = t/(1/a -5)

 

b) p = a + x + ax

p - a = x (1 + a) /  (1 +a)

x = (p - a)/(1+a)

 

c) m = (x+1)p - 3x

m = px + p - 3x

m - p = x(p -3) / (p-3)

x = (m-p)/(p-3)

 

d) w = 1/x + p

w - p = 1/x

x = 1/(w-p)

 

mam nadzieję, że pomogłam :)

Answer 2

a) P= d/M RT ; M
mnożymy najpierw przez RT
PRT=d/M
teraz przez m i dzielimy przez PRT
PRTM=d
M=d/PRT
b) f = 9/5 c + 32 ;c
f-32=9/5c
c=5/9(f-32)
c) s = vt + at²/2 ; a
2s-vt=at²
a=2s-v/t
d) F = G Mn/r² ; m
Fr²=GMn
Fr²/Gn=M

 

 

a) t = x/a - 5x//:a
ta=x-5xa
x-5xa=ta
x(1-5a)=ta//:(1-5a)
x=ta/1-5a
b) p = a + x + ax
a+x+ax=p/-a
x+ax=p-a
x(1+a)=p-a//:(1+a)
x=p-a/1+a
c) m = (x+1)p - 3x
m=px+p-3x
px+p-3x=m/-p
px-3x=m-p
x(p-3)=m-p//:(p-3)
x=m-p/p-3
d) w = 1/x + p//*x
wx=1+px//-px
wx-px=1
x(w-p)=1//:(w-p)
x=1/w-p