Question

Bagaimana persamaan kuadrat ini?

Answer 1

10)
[3/3^(x-1)]² = ³√(1/9)
3²/3^(2x-2) = 3^(-2)^⅓
3².3^(-2x+2)= 3^(-⅔)
3^(-2x+2+2)= 3^(-⅔)
3^(-2x+4)=3^(-⅔)
-2x+4=-⅔
-2x=-⅔-12/3
-2x=-14/3
x=-14/3 : -2
x=-14/-6
x=7/3

8^x
=2³^(7/3)
=2^7
=128

Jawaban D

11).
9^(2x²-6x+1)=27^(2x-4)
3²^(2x²-6x+1)=3³^(2x-4)
3^(4x²-12x+2)=3^(6x-12)
4x²-12x+2=6x-12
4x²-12x-6x+2+12=0
4x²-18x+14=0
(4x-14)(x-1)
x1=14/4=7/2 atau x2=1

x2-x1=1-7/2=2/2-7/2=-5/2