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1.⇔x∈(-∞,0)u(2,∞)
2.
x(x-2)≥x²
x(x-2-x)≥0
-2x≥0⇔x≤0⇔x∈(-∞,0>
D=(-∞,0)
Wyznaczam f. odwrotną do f(x)
y²=ln[(x-2)/x]
, D=(0,∞)
dołączam wykresy f. odwrotnych