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B= (x:x∈R i (x-2)²+(x-1)²≤x²)
A:
-2x²+9x-9<0
Δ=81-72=9
√Δ=3
x1=(-9+3)/(-4)=3/2
x2=(-9-3)/(-4)=3
(x-3)(x-3/2)<0
A:x∈(3/2;3)
B:
(x-2)²+(x-1)²≤x²
x²-4x+4+x²-2x+1-x²≤0
x²-6x+5≤0
Δ=36-20=16 √Δ=4
x1=1
x2=5
(x-1)(x-5)≤0
B:x∈<1;5>
A\B: zauważamy że A zawiera się w B więc A\B = zbór pusty