Hay dos maneras de resolver el problema:
1ro Halla todos los números primos y sumarlos:
10 + 12 + 14 + 16 + 18 + 20 + 22 + 24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 + 48 + 50 + 52 + 54 + 56 + 58 + 60 62 + 64 + 66 + 68 + 70 + 72 + 74 + 76 + 78 + 80 + 82 + 84 + 86 + 88 + 90 + 92 + 94 + 96 + 98 = 2430
2da manera:
10 + 12 + 14 + 16 18 ..... 98
[tex]\frac{(98+10)*45 }{2}[/tex] [tex]\frac{180*45}{2}[/tex]
4860 ÷ 2 = 2430
Respuesta:
Datos
[tex]n = numero \: de \: terminos = 45[/tex]
[tex] a_{1} = primer \: termino = 10[/tex]
[tex]a_{n} = ultimo \: termino = 98[/tex]
Resolución
[tex] s_{n} = \frac{n(a_{1} + a_{n}) }{2} [/tex]
[tex]s_{n} = \frac{45(10 + 98) }{2} [/tex]
[tex]s_{n} = 2430[/tex]
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Hay dos maneras de resolver el problema:
1ro Halla todos los números primos y sumarlos:
10 + 12 + 14 + 16 + 18 + 20 + 22 + 24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 + 48 + 50 + 52 + 54 + 56 + 58 + 60 62 + 64 + 66 + 68 + 70 + 72 + 74 + 76 + 78 + 80 + 82 + 84 + 86 + 88 + 90 + 92 + 94 + 96 + 98 = 2430
2da manera:
10 + 12 + 14 + 16 18 ..... 98
[tex]\frac{(98+10)*45 }{2}[/tex] [tex]\frac{180*45}{2}[/tex]
4860 ÷ 2 = 2430
Respuesta:
Datos
[tex]n = numero \: de \: terminos = 45[/tex]
[tex] a_{1} = primer \: termino = 10[/tex]
[tex]a_{n} = ultimo \: termino = 98[/tex]
Resolución
[tex] s_{n} = \frac{n(a_{1} + a_{n}) }{2} [/tex]
[tex]s_{n} = \frac{45(10 + 98) }{2} [/tex]
[tex]s_{n} = 2430[/tex]