[tex]Si: \dfrac{a}{b} = a^{2} + b -1\\\\Halla: A = \sqrt[3]{\frac{5}{6} -3}[/tex]
Respuesta: A = 3
Explicación paso a paso:
[tex]Como: \dfrac{a}{b} = a^{2} +b-1\\Entonces: \dfrac{5}{6} = 5^{2} +6-1 = 25 + 6 - 1 = 30\\\\A = \sqrt[3]{\frac{5}{6} -3} = \sqrt[3]{30-3} = \sqrt[3]{27} = 3[/tex]
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[tex]Si: \dfrac{a}{b} = a^{2} + b -1\\\\Halla: A = \sqrt[3]{\frac{5}{6} -3}[/tex]
Respuesta: A = 3
Explicación paso a paso:
[tex]Como: \dfrac{a}{b} = a^{2} +b-1\\Entonces: \dfrac{5}{6} = 5^{2} +6-1 = 25 + 6 - 1 = 30\\\\A = \sqrt[3]{\frac{5}{6} -3} = \sqrt[3]{30-3} = \sqrt[3]{27} = 3[/tex]
Respuesta: A = 3
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Michael Spymore