Respuesta:
Explicación paso a paso:
15.
Los ángulos internos:
[tex]A = 180-\alpha[/tex]
[tex]B = 180-2\alpha[/tex]
[tex]C = 180-3\alpha[/tex]
[tex]D = 180-4\alpha[/tex]
Suma de los ángulos internos de un cuadrilátero igual a 360°.
[tex]A+B+C+D = 360[/tex]
[tex](180-\alpha )+(180-2\alpha ) +(180-3\alpha )+(180-4\alpha )=360[/tex]
[tex]720-10\alpha =360[/tex]
[tex]-10\alpha =360-720[/tex]
[tex]-10\alpha =-360[/tex]
[tex]\alpha = \frac{-360}{-10}[/tex]
[tex]Luego: \alpha =36^{0}[/tex]
Respuesta: E ) 36°
______________________________________________
16.
[tex]Base-mayor: B = 12[/tex]
[tex]Base-menor: b =8[/tex]
[tex]Mediana: x=?[/tex]
[tex]x = \frac{B+b}{2}[/tex]
[tex]x = \frac{12+8}{2} = \frac{20}{2}[/tex]
[tex]x = 10[/tex]
Respuesta: E ) 10
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Verified answer
Respuesta:
Explicación paso a paso:
15.
Los ángulos internos:
[tex]A = 180-\alpha[/tex]
[tex]B = 180-2\alpha[/tex]
[tex]C = 180-3\alpha[/tex]
[tex]D = 180-4\alpha[/tex]
Suma de los ángulos internos de un cuadrilátero igual a 360°.
[tex]A+B+C+D = 360[/tex]
[tex](180-\alpha )+(180-2\alpha ) +(180-3\alpha )+(180-4\alpha )=360[/tex]
[tex]720-10\alpha =360[/tex]
[tex]-10\alpha =360-720[/tex]
[tex]-10\alpha =-360[/tex]
[tex]\alpha = \frac{-360}{-10}[/tex]
[tex]Luego: \alpha =36^{0}[/tex]
Respuesta: E ) 36°
______________________________________________
16.
[tex]Base-mayor: B = 12[/tex]
[tex]Base-menor: b =8[/tex]
[tex]Mediana: x=?[/tex]
[tex]x = \frac{B+b}{2}[/tex]
[tex]x = \frac{12+8}{2} = \frac{20}{2}[/tex]
[tex]x = 10[/tex]
Respuesta: E ) 10