Question

Ayudenme plisssssss :v

Answer 1

Explicación paso a paso:

hole °

E = Ecuación #1

[tex]( \frac{5}{11} ) ^{ - 1} + ( \frac{5}{4} ) ^{ - 1} + ( \frac{5}{3} ) ^{ - 1} + ( \frac{5}{4} ) ^{ - 1} = [/tex]

Usamos la regla del expontente negativo !

[tex] = \frac{1}{ \frac{5}{11} } + \frac{1}{ \frac{5}{4} } + \frac{1}{ \frac{5}{3} } + \frac{1}{ \frac{5}{2} } [/tex]

[tex] = \frac{11}{5} + \frac{4}{5} + \frac{3}{5} + \frac{2}{5} [/tex]

[tex] = \frac{20}{5} [/tex]

[tex] = 4[/tex]

T. Ecuación #2

[tex] {6}^{ - 4(0)} + {3}^{ - 5(0)} + {2}^{ - 6(0)} = [/tex]

[tex] = {6}^{ - 1} + {3}^{ - 1} + {2}^{ - 1} [/tex]

[tex] = \frac{1}{6} + \frac{1}{3} + \frac{1}{2} [/tex]

[tex] = \frac{1}{6} + \frac{2}{6} + \frac{3}{6} [/tex]

[tex] = \frac{6}{6} [/tex]

[tex] = 1[/tex]

Nos pide F = (E×T ) ^2

SUSTITUIMOS los valores obtenidos✓

[tex]f = (4 \times 1) ^{2} [/tex]

[tex]f = {4}^{2} [/tex]

[tex]f = 16[/tex]

Atte ° David