Respuesta:
12 litros
Explicación:
PV=nRT
P = 4.1 atm
R = 0.082 atm.L/mol.K
T = 27 °C = 300 K
1 mol =
[tex]6 \times {10}^{23} moleculas[/tex]
En
[tex]12 \times {10}^{23} moleculas[/tex]
habrán 2 mol de metano
n = 2 mol
4.1 x V=2 x 0.082 x 300
4.1 x V = 49.2
V = 49.2/4.1
V = 12
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Respuesta:
12 litros
Explicación:
PV=nRT
P = 4.1 atm
R = 0.082 atm.L/mol.K
T = 27 °C = 300 K
1 mol =
[tex]6 \times {10}^{23} moleculas[/tex]
En
[tex]12 \times {10}^{23} moleculas[/tex]
habrán 2 mol de metano
n = 2 mol
4.1 x V=2 x 0.082 x 300
4.1 x V = 49.2
V = 49.2/4.1
V = 12