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δ = 3x + 15°
β + δ = 90°
Entonces:
6x - 25° + 3x + 15° = 90°
6x + 3x = 90° + 25° - 15°
9x = 100°
x = 100°/9
Para encontrar el otro angulo , por ser opuesto por el vertice " 90° + δ = γ "
90° + δ = γ
90° + 3 ( 100° / 9 ) + 15° = γ
105° + 100°/3 = γ
415°/3 = γ
Solución :
β → 6 ( 100°/9 ) - 25° = 41° 40'
δ → 3 ( 100°/9 ) + 15° = 48° 20'
γ → 138° 20'