Question

AYUDEN PE DOY CORONA

al menos 1 problema :v

Answer 1

Explicación paso a paso:

TE AYUDO "PE"

1)

[tex] \frac{ {2}^{3} {2}^{4} {2}^{5} }{ {2}^{12} } [/tex]

[tex] \frac{ {2}^{3 + 4 + 5} }{ {2}^{12} } [/tex]

[tex] \frac{ {2}^{12} }{ {2}^{12} } [/tex]

1

2)

[tex] \frac{ {3}^{6} }{ {3}^{7} } + \frac{5}{3} [/tex]

[tex] \frac{1}{3} + \frac{5}{3} [/tex]

[tex] \frac{6}{3} [/tex]

2

3)

FACTORIZE

[tex]( {2}^{3} + {2}^{2} + 2 + 1) \times {2}^{x - 3} = 30[/tex]

[tex](8 + 4 + 3) \times {2}^{x - 3} = 30[/tex]

[tex]15 \times {2}^{x - 3} = 30[/tex]

[tex] {2}^{x - 3} = 2[/tex]

[tex]x - 3 = 1[/tex]

x=4

REEMPLAZO

(5x+2)²

(5(4)+2)²

(20+2)²

(22)²=484