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casos favorables/ casos posibles = 1/6
mayor que 4, osea que salga 5, 6. es decir 2 opcipones, entonces la probabilidad, será:
p = 2/6 = 1/3
de las ecuaciones tenemos:
m+3n = 50
m-2n = 5, restamos
3n + 2n = 50-5
5n = 45 , ------> n = 9 , m = 23
piden m+n = 23+9 = 32