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A=l^2
Despejamos l y sustituimos:
l=√A
l=√144
l=12 cm
Quiere decir que AG=12. Ahora, AH es 2/3 de AG, entonces:
AH=2/3×AG=2/3(12)=8 cm
AH mide 8 cm.
Determinamos el área de ABEH:
ABEH=b×a
ABEH=8×12=96 cm^2
Y finalmente, BCDE es ACDH menos ABEH, entonces:
BCDE=ACDH-ABEH
BCDE=144-96
BCDE=48 cm^2