Holi
La suma total de los ángulos internos de un pentágono es de 540°
[tex]Θ - 2x + Θ + Θ + y + Θ + 2x + Θ - y = 540 \\ \\ 5Θ = 540 \\ \\ Θ = \frac{540}{5} \\ \\ Θ = 108[/tex]
[tex]5Θ = 540 \\ \\ 5(108) = 540 \\ \\ 540 = 540[/tex]
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Holi
La suma total de los ángulos internos de un pentágono es de 540°
[tex]Θ - 2x + Θ + Θ + y + Θ + 2x + Θ - y = 540 \\ \\ 5Θ = 540 \\ \\ Θ = \frac{540}{5} \\ \\ Θ = 108[/tex]
Comprobación
[tex]5Θ = 540 \\ \\ 5(108) = 540 \\ \\ 540 = 540[/tex]
Dicha solución es correcta
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