Respuesta:
[tex]4\sqrt{2} cm[/tex] ó [tex]5.66cm[/tex]
Explicación paso a paso:
[tex]Diagonal : d = 8cm[/tex]
[tex]Lado: x = ?[/tex]
Por Pitágoras:
[tex]x^{2} +x^{2} = d^{2}[/tex]
[tex]x^{2} +x^{2} = (8cm)^{2}[/tex]
[tex]2x^{2} = 64cm^{2}[/tex]
[tex]x^{2} = \frac{64cm^{2} }{2}[/tex]
[tex]x^{2} = 32cm^{2}[/tex]
[tex]x = \sqrt{32cm^{2} }= \sqrt{16* 2cm^{2} }[/tex]
[tex]x = 4\sqrt{2} cm[/tex]
Que tenes que hacer
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Verified answer
Respuesta:
[tex]4\sqrt{2} cm[/tex] ó [tex]5.66cm[/tex]
Explicación paso a paso:
[tex]Diagonal : d = 8cm[/tex]
[tex]Lado: x = ?[/tex]
Por Pitágoras:
[tex]x^{2} +x^{2} = d^{2}[/tex]
[tex]x^{2} +x^{2} = (8cm)^{2}[/tex]
[tex]2x^{2} = 64cm^{2}[/tex]
[tex]x^{2} = \frac{64cm^{2} }{2}[/tex]
[tex]x^{2} = 32cm^{2}[/tex]
[tex]x = \sqrt{32cm^{2} }= \sqrt{16* 2cm^{2} }[/tex]
[tex]x = 4\sqrt{2} cm[/tex]
Respuesta:
Explicación paso a paso:
Que tenes que hacer