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2- y=log_5 81; 3^y=3^4; y=4
3- y=log_(1/5) 5; (1/5)^y=5; (1/5)^y=5^-1; y=-1
log_a 27=3; a^3=27=3^3, a=3
log_a (1/2)=-1; a^-1=1/2; 2^-1=1/2; a=2
el log de 1/4 está mal realizado, es una falsa igualdad